1n^2-2-4=77

Solution for 1n^2-2-4=77 equation:

1n^2-2-4=77

We move all terms to the left:

1n^2-2-4-(77)=0

We add all the numbers together, and all the variables

n^2-83=0

a = 1; b = 0; c = -83;
Δ = b2-4ac
Δ = 02-4·1·(-83)
Δ = 332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{332}=\sqrt{4*83}=\sqrt{4}*\sqrt{83}=2\sqrt{83}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{83}}{2*1}=\frac{0-2\sqrt{83}}{2}
=-\frac{2\sqrt{83}}{2}
=-\sqrt{83}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{83}}{2*1}=\frac{0+2\sqrt{83}}{2}
=\frac{2\sqrt{83}}{2}
=\sqrt{83}
$